307x Filetype PDF File size 0.29 MB Source: ph.qmul.ac.uk
Dynamics of Rigid Bodies
A rigid body is one in which the distances between constituent particles is constant
throughout the motion of the body, i.e. it keeps its shape.
There are two kinds of rigid body motion:
1. Translational
Rectilinear forces acting.
Particles move on straight-
line paths.
2. Rotational
Rotational forces, i.e.
torques, acting.
Particles move on circular
paths
Kinematics of Rigid Bodies
dθ dω d2θ Angle θ is in
s = Rθ ω= dt α= dt = dt2 radians
Let α be a constant.
dθ
d2θ dt = αt +C
Then, dt2 = α Integrating,
dθ
Let ω = ω at t = 0, ω= =αt+ω
0 dt 0
COMPARE THESE
Integrating, θ=½αt2+ω t+c WITH THE
0
EQUATIONS FOR
Let θ = 0 at t = 0, θ=½αt2 +ω t LINEAR MOTION
0
Note: θ is in radians
Angular Momentum
Angular momentum is the rotational equivalent of linear momentum. It is a
conserved quantity
A rigid body can be thought
y of as a large number of
r particles i, at positions A ,
ω i
with masses m, at position
i
vectors from an origin on the
axis of r, at distances R from
A i i
i the axis, and with velocities
v.
i
x
z
The particle at the point
A has linear momentum p = mv and Angular Momentum
i i i
about the origin
L =r ×p
i i i
ˆ
=mr ×v =mrvn
i i i i i i
ˆ
where n is unit vector normal to both r and p.
i i
Note that L is not generally parallel to the axis of rotation.
Moment of Inertia
The component of the angular momentum in the y-direction, i.e. along th axis of
rotation, is
L =mrv sinθ
iy i i i i
However, r sin θ= R, so
i i i
L =m Rv
i i i i
The magnitude of ω is the same for all points, so we drop the index i, and v = Rω.
i i i
Then
L =mR2ω
iy i i
Summing or integrating over all points,
L =L +L +K= L =ω mR2
y 1y 2y ∑ iy ∑ i i
i i
This sum, I = ∑m R2 is called the Moment of Inertia , and L = Iω (c.f. p = mv)
i i
i
Moment of Inertia of Potato-Shapes
The Moment of Inertia depends on the axis of rotation.
The Angular Momentum is generally not parallel to the axis of rotation.
For a body of general shape (an asteroid, a potato . . .) there are three mutually
perpendicular axes for which the angular momentum is parallel to the axis. These are
called the Principal Axes of intertia and the moments of inertia about them are the
Principal Moments of Inertia.
For bodies of higher symmetry than potatoes, the Principal Axes are generally Axes
of Symmetry.
Angular Momentum Examples:
Two masses m are going
round the z-axis, at radius R,
in the x-y plane, with speed v
= Rω.
L=r×mv for eachmass
r = R
v = Rω
L =2mR2ω for the pair
Direction of L is at right angles to r and v, i.e. in same direction as ω, i.e.
L=2mR2ω=Iω
and I = 2mR
Now incline the masses to the
axis.
L L=r×mv for eachmass
r = R
v = Rωsinϕ
L =2mR2ωsinϕ for the pair
Direction of L is at right angles to r and v, i.e. at ϕ to ω, i.e. it precesses about z.
2 2 2 2
L = 2mR sin ϕ ω, and I = 2mR sin ϕ about the z-axis.
z
Calculation of Moments of Inertia
R is distance to
I = ∑m R2 i
i i axis of rotation
i
If an object is considered to consist of elemental particles of mass dm, then
dm=ρdV
and the sum becomes an integral over the volume. If the density ρ is constant,
it comes out of the integral and
I = ∫R2dm =ρ∫R2dV
V V
Note that ∫ R2dV is a purely geometrical factor
V
Example: Moment of Inertia of a thin rod rotated about one end.
Cross-sectional area
S, length L, density ρ.
Element dV is disc of area S, distasnce from axis x, thickness dx.
( 2 )
i.e. dV = Sdx, dm = ρSdx, dI = ρSx dx
So we have
L 2 1 3 1 2
I = ρS∫ x dx = ρSL = ML
x=0 3 3
Example: Moment of Inertia of the same thin rod rotated about its centre.
L/2 3 3
=ρ 2 = 1ρ L −−L 1 2
I S∫ x dx S = ML
x=−L/2 3 8 8 12
2
In general, I = Mk . The length k is a characteristic
length of the object, called the Radius of Gyration –
compare with Centre of Gravity.
no reviews yet
Please Login to review.