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Chapter 7
Eigenvalues and Eigenvectors
7.1 Eigenvalues and Eigenvectors
7.2 Diagonalization
7.1 Eigenvalues and Eigenvectors
Eigenvalue problem:
n
If A is an nn matrix, do there exist nonzero vectors x in R
such that Ax is a scalar multiple of x?
Eigenvalue and eigenvector: Geometrical Interpretation
A:an nn matrix
:a scalar
n
x:a nonzero vector in R
Eigenvalue
Ax x
Eigenvector
1/53
Ex 1: (Verifying eigenvalues and eigenvectors)
2 0
1 0
A x x
1 2
0 1 0 1
Eigenvalue
2 0 1 2 1
Ax 2 2x
1 1
0 1 0 0 0
Eigenvector
Eigenvalue
2 0 0 0 0
Ax 1 (1)x
2 2
0 1 1 1 1
Eigenvector
2/53
Thm 7.1: (The eigenspace of A corresponding to )
If A is an nn matrix with an eigenvalue , then the set of all
eigenvectors of together with the zero vector is a subspace of
n
R . This subspace is called the eigenspace of .
Pf:
x1 and x2 are eigenvectors corresponding to
(i.e. Ax x , Ax x )
1 1 2 2
(1) A(x x ) Ax Ax x x (x x )
1 2 1 2 1 2 1 2
(i.e. x x is an eigenvector corresponding to λ)
1 2
(2) A(cx ) c(Ax ) c(x ) (cx )
1 1 1 1
(i.e. cx is an eigenvector corresponding to )
1
3/53
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