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Chapter 9 Matrices and Transformations
9MATRICES AND
TRANSFORMATIONS
Objectives
After studying this chapter you should
• be able to handle matrix (and vector) algebra with confidence,
and understand the differences between this and scalar algebra;
• be able to determine inverses of 2×2 matrices, recognising
the conditions under which they do, or do not, exist;
• be able to express plane transformations in algebraic and
matrix form;
• be able to recognise and use the standard matrix form for less
straightforward transformations;
• be able to use the properties of invariancy to help describe
transformations;
• appreciate the composition of simple transformations;
• be able to derive the eigenvalues and eigenvectors of a given
2×2 matrix, and interpret their significance in relation to an
associated plane transformation.
9.0 Introduction
A matrix is a rectangular array of numbers. Each entry in the
matrix is called an element. Matrices are classified by the
number of rows and the number of columns that they have; a
matrix A with m rows and n columns is an m×n (said 'm by n')
matrix, and this is called the order of A.
Example
Given
142
A = ,
3−10
then A has order 2×3 (rows first, columns second.) The elements
of A can be denoted by a , being the element in the ith row and
ij
jth column of A. In the above case, a =1, a =0, etc.
11 23
235
Chapter 9 Matrices and Transformations
Addition and subtraction of matrices is defined only for matrices of
equal order; the sum (difference) of matrices A and B is the matrix
obtained by adding (subtracting) the elements in corresponding
positions of A and B.
Thus
142 −123
A = and B =
3−10 43−3
065 22−1
⇒
A +B= and A −B = .
72−3 −1−43
However, if
23
C = ,
14
then C can neither be added to nor subtracted from either of A or B.
If you think of matrices as stores of information, then the addition
(or subtraction) of corresponding elements makes sense.
Example
A milkman delivers three varieties of milk Pasteurised (PA), Semi-
skimmed (SS) and Skimmed (SK)) to four houses (E, F, G and H)
over a two-week period. The number of pints of each type of milk
delivered to each house in week 1 is given in matrix M, while N
records similar information for week 2.
PA SS SK PA SS SK
E 843 E 478
F 12 0 3 F 10 0 5
=M =N
276 087
G G
H 690 H 8100
Then
12 11 11
22 0 8
M +N =
21513
14 19 0
records the total numbers of pints of each type of milk delivered to
each of the houses over the fortnight,
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Chapter 9 Matrices and Transformations
and
−435
−202
N −M =
−211
210
records the increase in delivery for each type of milk for each of
the houses in the second week.
Suppose now that we consider the 3×2 matrix, P, giving the prices
of each type of milk, in pence, as charged by two dairy companies:
12
PA 35 36
SS 32 30=P
SK 27 27
What are the possible weekly milk costs to each of the four
households?
Define the cost matrix as
12
cc
E
11 12
c c
F
21 22 = C
c c
G
31 32
c c
H
41 42
Now c is the cost to household E if company 1 delivers the milk
11
(in the week for which the matrix M records the deliveries)
and so
c =8×35+4×32+3×27
11
=489p
Essentially this is the first row of M 'times' the first
843
[]
35
column 32 of P.
27
Similarly, for example, c can be thought of as the 'product' of the
32
36
third row of M, 276 30
, with the second column of P, , so
[]
27
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Chapter 9 Matrices and Transformations
that c =2×36+7×30+6×27
32
=444p
This is the cost to household G if they get company 2 to deliver
their milk.
Matrix multiplication is defined in this way. You will see that
multiplication of matrices X and Y is only possible if
= the number of rows of Y
the number of columns X
Then, if X is an a×b matrix and B a c×d matrix, the
() ()
product matrix XY exists if and only if b = c and XY is then an
a×d matrix. Thus, for P = XY ,
()
P= p ,
()
ij
where the entry p is the scalar product of the ith row of X
ij
(taken as a row vector) with the jth column of Y (taken as a
column vector).
Example
Find AB when
25
142
A = , B = 20
3−10
−13
Solution
A is a 2×3 matrix, B is a 3×2 matrix. Since the number of
columns of A = the number of rows of B, the product matrix AB
exists, and has order 2×2.
p p
P=AB = 11 12
p21 p22
2
p = 142 . 2=2+8−2=8
11 [] , etc
−1
giving
811
P=
415
238
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